Each of eight primitive of java data types has a class dedicated to it, are known as wrapper classes, because they wrap the primitive data type into an object of that class. The wrapper classes are part of the java.lang package, which is imported by default into all Java programs. Each of eight primitive of java data types has a class dedicated to it, are known as wrapper classes, because they wrap the primitive data type into an object of that class. The wrapper classes are part of the java.lang package, which is imported by default into all Java programs. We recommend reading this tutorial, in the sequence listed in the left menu. Java is an object oriented language and some concepts may be new. Take breaks when needed, and go over the examples as many times as needed.
Active6 years, 3 months ago
i have follow this tutorial to run a java class as a window service.
I did a minor changes i change the HellowWroldServer class to as follow
What this code do is simple it create a 'new.txt' file in D location. I follow the rest tutorial. I didn't get any error and successfully install the window service.
Now after installation i expected when i run the window service it will create a file in the D location but i am wrong. My window service didn't create new.txt file in the D location. anyone can tell me what is the problem??
dsolimano
7,69233 gold badges4141 silver badges5757 bronze badges
Waqas AliWaqas Ali
84244 gold badges2525 silver badges5050 bronze badges
1 Answer
When you are running as a Windows Service, the user is by default the SYSTEM user. That user has much different permissions than the user you are logged on as. Please make sure that you actually have access.
In the application you wrote though, if this fails then you should be getting an IOException. Did you see anything in the wrapper.log file?
If you want to change the user that the service runs as, see the following page:http://wrapper.tanukisoftware.com/doc/english/prop-ntservice-account.html
I hope this helps.
Cheers,Leif
Leif MortensonLeif Mortenson
Not the answer you're looking for? Browse other questions tagged javawindows-services or ask your own question.
Active6 years, 6 months ago
I have simply donwloaded JSW community edition, unwrapped into a directory:
c:servicetest So here i have a bin, conf, lib and log subdirs, among others.From now on this will be (root). I referenced the (root)/lib/wrapper.jar into my ide (netbeans) and create a very simple service (remember the class name is Main):
As you see, it basically does nothing but logging a message. But actually it neither starts.
I compiled the project (MyProject.jar), copied the jar into the (root) directory and modified the (root)/config/wrapper.conf adding:
and
Then i've installed the service in command line, with:
then i've started the service, either via services.msc control panel or via
In logs/wrapper.log i get:
UPDATE 1
Following Tanuki Software advice, i've set in my (root)/config/wrapper.conf (well, uncommented since it already was):
And now i get this:
But given my very simple implementation, i cannot guess what is going wrong.
AgostinoX
AgostinoXAgostinoX
3,7431717 gold badges6565 silver badges111111 bronze badges
1 Answer
rather than extending WrapperSimpleApp, your main class should implement the org.tanukisoftware.wrapper.WrapperListener interface.
You can find a very detailed description about implementing the interface on our website:http://wrapper.tanukisoftware.com/doc/english/integrate-listener.html
Please let me know if you have any further questions about the implementation and/or the configuration properties in your conf file.
They are also used by Mozilla Firefox, Thunderbird, SeaMonkey, and Sunbird to store themes and.NOTE: The Java Runtime Environment is also referred to as the Java Virtual Machine (JVM). Jar file games. They are compressed using compression and may optionally be using the jarsigner tool included with the Java. JAR files may be created with the jar tool, and they can be accessed using Java's java.util.jar.JAR files are used for some mobile games supported by Java-enabled mobile devices.
Another advise which comes in handy for me sometimes, is rather than running your application immediately as service, I find it easier to do the integration by running first as console application, because you can see the output directly on your console. Once everything seems working, I go ahead and install/run as service. To run as console application, you would run for example:
You can also turn on debug output for the Wrapper by setting
in your conf file.
Edit due to the comment:
if your application is actually as simple as you describe, then just write your application as normal Java application without any Wrapper API parts.
You can use the WrapperSimpleApp to run your application out of the box with codeless integration into the Wrapper.
All you need to do is set the following properties in your conf file:
With this configuration, the Wrapper will be able to run your application as windows service.
![]()
UPDATE2
Java Service Wrapper Tutorial Video
I'm not sure what your code exactly looks like, but it seems you are calling WrapperManager.stop() in your main class..
Following the initial example class, I have modified the class, so it is not using any Wrapper-API (which for an simple application is not necessary):
After compile and creating the jar, the necessary properties in the conf file are:
Java Service Wrapper Tutorial Online
cheers,
NaytzyrhcNaytzyrhc
Java Wrapper TypesNot the answer you're looking for? Browse other questions tagged javajava-service-wrapper or ask your own question.Comments are closed.
|
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |